4(2n+1)=7(3n+6)+8

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Solution for 4(2n+1)=7(3n+6)+8 equation: 



4(2n+1)=7(3n+6)+8

We move all terms to the left:

4(2n+1)-(7(3n+6)+8)=0

We multiply parentheses

8n-(7(3n+6)+8)+4=0



We calculate terms in parentheses: -(7(3n+6)+8), so:

7(3n+6)+8

We multiply parentheses

21n+42+8

We add all the numbers together, and all the variables

21n+50

Back to the equation:

-(21n+50)



We get rid of parentheses

8n-21n-50+4=0

We add all the numbers together, and all the variables

-13n-46=0

We move all terms containing n to the left, all other terms to the right

-13n=46

n=46/-13

n=-3+7/13

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