7(7c*1)-4c=13(3c-2)

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Solution for 7(7c*1)-4c=13(3c-2) equation: 



7(7c*1)-4c=13(3c-2)

We move all terms to the left:

7(7c*1)-4c-(13(3c-2))=0

We add all the numbers together, and all the variables

7(+7c*1)-4c-(13(3c-2))=0

We add all the numbers together, and all the variables

-4c+7(+7c*1)-(13(3c-2))=0

We multiply parentheses

-4c+49c-(13(3c-2))=0



We calculate terms in parentheses: -(13(3c-2)), so:

13(3c-2)

We multiply parentheses

39c-26

Back to the equation:

-(39c-26)



We add all the numbers together, and all the variables

45c-(39c-26)=0

We get rid of parentheses

45c-39c+26=0

We add all the numbers together, and all the variables

6c+26=0

We move all terms containing c to the left, all other terms to the right

6c=-26

c=-26/6

c=-4+1/3

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