2/5x-5/7x=x+1

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Solution for 2/5x-5/7x=x+1 equation: 



2/5x-5/7x=x+1

We move all terms to the left:

2/5x-5/7x-(x+1)=0



Domain of the equation: 5x!=0

x!=0/5

x!=0

x∈R





Domain of the equation: 7x!=0

x!=0/7

x!=0

x∈R



We get rid of parentheses

2/5x-5/7x-x-1=0

We calculate fractions


-x+14x/35x^2+(-25x)/35x^2-1=0

We add all the numbers together, and all the variables

-1x+14x/35x^2+(-25x)/35x^2-1=0

We multiply all the terms by the denominator


-1x*35x^2+14x+(-25x)-1*35x^2=0

We add all the numbers together, and all the variables

14x-1x*35x^2+(-25x)-1*35x^2=0

Wy multiply elements

-35x^3-35x^2+14x+(-25x)=0

We get rid of parentheses

-35x^3-35x^2+14x-25x=0

We do not support expression: x^3

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