4(2m+2)-2=7(m-)+16

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Solution for 4(2m+2)-2=7(m-)+16 equation: 



4(2m+2)-2=7(m-)+16

We move all terms to the left:

4(2m+2)-2-(7(m-)+16)=0

We add all the numbers together, and all the variables

4(2m+2)-(7(+m)+16)-2=0

We multiply parentheses

8m-(7(+m)+16)+8-2=0



We calculate terms in parentheses: -(7(+m)+16), so:

7(+m)+16

We multiply parentheses

7m+16

Back to the equation:

-(7m+16)



We add all the numbers together, and all the variables

8m-(7m+16)+6=0

We get rid of parentheses

8m-7m-16+6=0

We add all the numbers together, and all the variables

m-10=0

We move all terms containing m to the left, all other terms to the right

m=10

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