4(y+3)-6(y+1)=4(3y+4)-2(8+6y)

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Solution for 4(y+3)-6(y+1)=4(3y+4)-2(8+6y) equation: 



4(y+3)-6(y+1)=4(3y+4)-2(8+6y)

We move all terms to the left:

4(y+3)-6(y+1)-(4(3y+4)-2(8+6y))=0

We add all the numbers together, and all the variables

4(y+3)-6(y+1)-(4(3y+4)-2(6y+8))=0

We multiply parentheses

4y-6y-(4(3y+4)-2(6y+8))+12-6=0



We calculate terms in parentheses: -(4(3y+4)-2(6y+8)), so:

4(3y+4)-2(6y+8)

We multiply parentheses

12y-12y+16-16

We add all the numbers together, and all the variables



Back to the equation:

-()



We add all the numbers together, and all the variables

-2y=0

y=0/-2

y=0

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