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6/x+2/3x=2
We move all terms to the left:
6/x+2/3x-(2)=0
Domain of the equation: x!=0
x∈R
Domain of the equation: 3x!=0We calculate fractions
x!=0/3
x!=0
x∈R
18x/3x^2+2x/3x^2-2=0
We multiply all the terms by the denominator
18x+2x-2*3x^2=0
We add all the numbers together, and all the variables
20x-2*3x^2=0
Wy multiply elements
-6x^2+20x=0
a = -6; b = 20; c = 0;
Δ = b2-4ac
Δ = 202-4·(-6)·0
Δ = 400
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{400}=20$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(20)-20}{2*-6}=\frac{-40}{-12} =3+1/3 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(20)+20}{2*-6}=\frac{0}{-12} =0 $
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