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3/4(2x-5)=-6+5/4(3x+9)
We move all terms to the left:
3/4(2x-5)-(-6+5/4(3x+9))=0
Domain of the equation: 4(2x-5)!=0
x∈R
Domain of the equation: 4(3x+9))!=0We calculate fractions
x∈R
(12x3/(4(2x-5)*4(3x+9)))+(-20x2/(4(2x-5)*4(3x+9)))=0
We calculate terms in parentheses: +(12x3/(4(2x-5)*4(3x+9))), so:
12x3/(4(2x-5)*4(3x+9))
We multiply all the terms by the denominator
12x3
We add all the numbers together, and all the variables
12x^3
We do not support expression: x^3
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