4(2k+3)=-3(k-1)+31

Solution for 4(2k+3)=-3(k-1)+31 equation:

4(2k+3)=-3(k-1)+31

We move all terms to the left:

4(2k+3)-(-3(k-1)+31)=0

We multiply parentheses

8k-(-3(k-1)+31)+12=0


We calculate terms in parentheses: -(-3(k-1)+31), so:

-3(k-1)+31

We multiply parentheses

-3k+3+31

We add all the numbers together, and all the variables

-3k+34

Back to the equation:

-(-3k+34)


We get rid of parentheses

8k+3k-34+12=0

We add all the numbers together, and all the variables

11k-22=0

We move all terms containing k to the left, all other terms to the right

11k=22

k=22/11

k=2