2/3(15x+30)=1/3(102-12x)

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Solution for 2/3(15x+30)=1/3(102-12x) equation: 



2/3(15x+30)=1/3(102-12x)

We move all terms to the left:

2/3(15x+30)-(1/3(102-12x))=0



Domain of the equation: 3(15x+30)!=0

x∈R





Domain of the equation: 3(102-12x))!=0

x∈R



We add all the numbers together, and all the variables

2/3(15x+30)-(1/3(-12x+102))=0

We calculate fractions


(6x(-)/(3(15x+30)*3(-12x+102)))+(-3x1/(3(15x+30)*3(-12x+102)))=0



We calculate terms in parentheses: +(6x(-)/(3(15x+30)*3(-12x+102))), so:

6x(-)/(3(15x+30)*3(-12x+102))

We add all the numbers together, and all the variables

6x0/(3(15x+30)*3(-12x+102))

We multiply all the terms by the denominator


6x0

We add all the numbers together, and all the variables

6x

Back to the equation:

+(6x)





We calculate terms in parentheses: +(-3x1/(3(15x+30)*3(-12x+102))), so:

-3x1/(3(15x+30)*3(-12x+102))

We multiply all the terms by the denominator


-3x1

We add all the numbers together, and all the variables

-3x

Back to the equation:

+(-3x)



We get rid of parentheses

6x-3x=0

We add all the numbers together, and all the variables

3x=0

x=0/3

x=0

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