48(3x-7)=40(2x+2)

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Solution for 48(3x-7)=40(2x+2) equation: 



48(3x-7)=40(2x+2)

We move all terms to the left:

48(3x-7)-(40(2x+2))=0

We multiply parentheses

144x-(40(2x+2))-336=0



We calculate terms in parentheses: -(40(2x+2)), so:

40(2x+2)

We multiply parentheses

80x+80

Back to the equation:

-(80x+80)



We get rid of parentheses

144x-80x-80-336=0

We add all the numbers together, and all the variables

64x-416=0

We move all terms containing x to the left, all other terms to the right

64x=416

x=416/64

x=6+1/2

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