4(2k+3)+10=2k-26

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Solution for 4(2k+3)+10=2k-26 equation: 



4(2k+3)+10=2k-26

We move all terms to the left:

4(2k+3)+10-(2k-26)=0

We multiply parentheses

8k-(2k-26)+12+10=0

We get rid of parentheses

8k-2k+26+12+10=0

We add all the numbers together, and all the variables

6k+48=0

We move all terms containing k to the left, all other terms to the right

6k=-48

k=-48/6

k=-8

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