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-1/2x=-3/8x-3
We move all terms to the left:
-1/2x-(-3/8x-3)=0
Domain of the equation: 2x!=0
x!=0/2
x!=0
x∈R
Domain of the equation: 8x-3)!=0We get rid of parentheses
x∈R
-1/2x+3/8x+3=0
We calculate fractions
(-8x)/16x^2+6x/16x^2+3=0
We multiply all the terms by the denominator
(-8x)+6x+3*16x^2=0
We add all the numbers together, and all the variables
6x+(-8x)+3*16x^2=0
Wy multiply elements
48x^2+6x+(-8x)=0
We get rid of parentheses
48x^2+6x-8x=0
We add all the numbers together, and all the variables
48x^2-2x=0
a = 48; b = -2; c = 0;
Δ = b2-4ac
Δ = -22-4·48·0
Δ = 4
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{4}=2$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-2)-2}{2*48}=\frac{0}{96} =0 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-2)+2}{2*48}=\frac{4}{96} =1/24 $
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