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(4x+3)(6x-2)=0
We multiply parentheses ..
(+24x^2-8x+18x-6)=0
We get rid of parentheses
24x^2-8x+18x-6=0
We add all the numbers together, and all the variables
24x^2+10x-6=0
a = 24; b = 10; c = -6;
Δ = b2-4ac
Δ = 102-4·24·(-6)
Δ = 676
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{676}=26$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(10)-26}{2*24}=\frac{-36}{48} =-3/4 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(10)+26}{2*24}=\frac{16}{48} =1/3 $
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