4(2b-3)-4=4(2b-4)

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Solution for 4(2b-3)-4=4(2b-4) equation: 



4(2b-3)-4=4(2b-4)

We move all terms to the left:

4(2b-3)-4-(4(2b-4))=0

We multiply parentheses

8b-(4(2b-4))-12-4=0



We calculate terms in parentheses: -(4(2b-4)), so:

4(2b-4)

We multiply parentheses

8b-16

Back to the equation:

-(8b-16)



We add all the numbers together, and all the variables

8b-(8b-16)-16=0

We get rid of parentheses

8b-8b+16-16=0

We add all the numbers together, and all the variables

=0

b=0/1

b=0

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