1/4x+5=-2x-4

Solution for 1/4x+5=-2x-4 equation:

1/4x+5=-2x-4

We move all terms to the left:

1/4x+5-(-2x-4)=0


Domain of the equation: 4x!=0

x!=0/4

x!=0

x∈R


We get rid of parentheses

1/4x+2x+4+5=0

We multiply all the terms by the denominator


2x*4x+4*4x+5*4x+1=0

Wy multiply elements

8x^2+16x+20x+1=0

We add all the numbers together, and all the variables

8x^2+36x+1=0

a = 8; b = 36; c = +1;
Δ = b2-4ac
Δ = 362-4·8·1
Δ = 1264
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{1264}=\sqrt{16*79}=\sqrt{16}*\sqrt{79}=4\sqrt{79}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(36)-4\sqrt{79}}{2*8}=\frac{-36-4\sqrt{79}}{16}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(36)+4\sqrt{79}}{2*8}=\frac{-36+4\sqrt{79}}{16}
$