3(k+12)=6

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Solution for 3(k+12)=6 equation: 



3(k+12)=6

We move all terms to the left:

3(k+12)-(6)=0

We multiply parentheses

3k+36-6=0

We add all the numbers together, and all the variables

3k+30=0

We move all terms containing k to the left, all other terms to the right

3k=-30

k=-30/3

k=-10

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