4(2a-5)-a=3(2-3a)+12

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Solution for 4(2a-5)-a=3(2-3a)+12 equation: 



4(2a-5)-a=3(2-3a)+12

We move all terms to the left:

4(2a-5)-a-(3(2-3a)+12)=0

We add all the numbers together, and all the variables

4(2a-5)-a-(3(-3a+2)+12)=0

We add all the numbers together, and all the variables

-1a+4(2a-5)-(3(-3a+2)+12)=0

We multiply parentheses

-1a+8a-(3(-3a+2)+12)-20=0



We calculate terms in parentheses: -(3(-3a+2)+12), so:

3(-3a+2)+12

We multiply parentheses

-9a+6+12

We add all the numbers together, and all the variables

-9a+18

Back to the equation:

-(-9a+18)



We add all the numbers together, and all the variables

7a-(-9a+18)-20=0

We get rid of parentheses

7a+9a-18-20=0

We add all the numbers together, and all the variables

16a-38=0

We move all terms containing a to the left, all other terms to the right

16a=38

a=38/16

a=2+3/8

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