4(2+3y)=56

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Solution for 4(2+3y)=56 equation: 



4(2+3y)=56

We move all terms to the left:

4(2+3y)-(56)=0

We add all the numbers together, and all the variables

4(3y+2)-56=0

We multiply parentheses

12y+8-56=0

We add all the numbers together, and all the variables

12y-48=0

We move all terms containing y to the left, all other terms to the right

12y=48

y=48/12

y=4

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