5(x-1)+4(x-3)=(x-1)-(1-x)

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Solution for 5(x-1)+4(x-3)=(x-1)-(1-x) equation: 



5(x-1)+4(x-3)=(x-1)-(1-x)

We move all terms to the left:

5(x-1)+4(x-3)-((x-1)-(1-x))=0

We add all the numbers together, and all the variables

5(x-1)+4(x-3)-((x-1)-(-1x+1))=0

We multiply parentheses

5x+4x-((x-1)-(-1x+1))-5-12=0



We calculate terms in parentheses: -((x-1)-(-1x+1)), so:

(x-1)-(-1x+1)

We get rid of parentheses

x+1x-1-1

We add all the numbers together, and all the variables

2x-2

Back to the equation:

-(2x-2)



We add all the numbers together, and all the variables

9x-(2x-2)-17=0

We get rid of parentheses

9x-2x+2-17=0

We add all the numbers together, and all the variables

7x-15=0

We move all terms containing x to the left, all other terms to the right

7x=15

x=15/7

x=2+1/7

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