(2a-4)+2(a-5)-3(a+1)=0

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Solution for (2a-4)+2(a-5)-3(a+1)=0 equation: 



(2a-4)+2(a-5)-3(a+1)=0

We multiply parentheses

(2a-4)+2a-3a-10-3=0

We get rid of parentheses

2a+2a-3a-4-10-3=0

We add all the numbers together, and all the variables

a-17=0

We move all terms containing a to the left, all other terms to the right

a=17

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