3(x-2)=(x-2)+(x+2)

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Solution for 3(x-2)=(x-2)+(x+2) equation: 



3(x-2)=(x-2)+(x+2)

We move all terms to the left:

3(x-2)-((x-2)+(x+2))=0

We multiply parentheses

3x-((x-2)+(x+2))-6=0



We calculate terms in parentheses: -((x-2)+(x+2)), so:

(x-2)+(x+2)

We get rid of parentheses

x+x-2+2

We add all the numbers together, and all the variables

2x

Back to the equation:

-(2x)



We add all the numbers together, and all the variables

x-6=0

We move all terms containing x to the left, all other terms to the right

x=6

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