4(2+3r)=8(r-6)

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Solution for 4(2+3r)=8(r-6) equation: 



4(2+3r)=8(r-6)

We move all terms to the left:

4(2+3r)-(8(r-6))=0

We add all the numbers together, and all the variables

4(3r+2)-(8(r-6))=0

We multiply parentheses

12r-(8(r-6))+8=0



We calculate terms in parentheses: -(8(r-6)), so:

8(r-6)

We multiply parentheses

8r-48

Back to the equation:

-(8r-48)



We get rid of parentheses

12r-8r+48+8=0

We add all the numbers together, and all the variables

4r+56=0

We move all terms containing r to the left, all other terms to the right

4r=-56

r=-56/4

r=-14

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