3(7a+2)+8a=6(1+a)

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Solution for 3(7a+2)+8a=6(1+a) equation: 



3(7a+2)+8a=6(1+a)

We move all terms to the left:

3(7a+2)+8a-(6(1+a))=0

We add all the numbers together, and all the variables

3(7a+2)+8a-(6(a+1))=0

We add all the numbers together, and all the variables

8a+3(7a+2)-(6(a+1))=0

We multiply parentheses

8a+21a-(6(a+1))+6=0



We calculate terms in parentheses: -(6(a+1)), so:

6(a+1)

We multiply parentheses

6a+6

Back to the equation:

-(6a+6)



We add all the numbers together, and all the variables

29a-(6a+6)+6=0

We get rid of parentheses

29a-6a-6+6=0

We add all the numbers together, and all the variables

23a=0

a=0/23

a=0

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