11c-20+c=-5(c+19)

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Solution for 11c-20+c=-5(c+19) equation: 



11c-20+c=-5(c+19)

We move all terms to the left:

11c-20+c-(-5(c+19))=0

We add all the numbers together, and all the variables

12c-(-5(c+19))-20=0



We calculate terms in parentheses: -(-5(c+19)), so:

-5(c+19)

We multiply parentheses

-5c-95

Back to the equation:

-(-5c-95)



We get rid of parentheses

12c+5c+95-20=0

We add all the numbers together, and all the variables

17c+75=0

We move all terms containing c to the left, all other terms to the right

17c=-75

c=-75/17

c=-4+7/17

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