4(18a-7)+40=3(4+22a)

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Solution for 4(18a-7)+40=3(4+22a) equation: 



4(18a-7)+40=3(4+22a)

We move all terms to the left:

4(18a-7)+40-(3(4+22a))=0

We add all the numbers together, and all the variables

4(18a-7)-(3(22a+4))+40=0

We multiply parentheses

72a-(3(22a+4))-28+40=0



We calculate terms in parentheses: -(3(22a+4)), so:

3(22a+4)

We multiply parentheses

66a+12

Back to the equation:

-(66a+12)



We add all the numbers together, and all the variables

72a-(66a+12)+12=0

We get rid of parentheses

72a-66a-12+12=0

We add all the numbers together, and all the variables

6a=0

a=0/6

a=0

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