-2x-3(3-4x)=3(x-4)-32

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Solution for -2x-3(3-4x)=3(x-4)-32 equation: 



-2x-3(3-4x)=3(x-4)-32

We move all terms to the left:

-2x-3(3-4x)-(3(x-4)-32)=0

We add all the numbers together, and all the variables

-2x-3(-4x+3)-(3(x-4)-32)=0

We multiply parentheses

-2x+12x-(3(x-4)-32)-9=0



We calculate terms in parentheses: -(3(x-4)-32), so:

3(x-4)-32

We multiply parentheses

3x-12-32

We add all the numbers together, and all the variables

3x-44

Back to the equation:

-(3x-44)



We add all the numbers together, and all the variables

10x-(3x-44)-9=0

We get rid of parentheses

10x-3x+44-9=0

We add all the numbers together, and all the variables

7x+35=0

We move all terms containing x to the left, all other terms to the right

7x=-35

x=-35/7

x=-5

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