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10/x+2x=12
We move all terms to the left:
10/x+2x-(12)=0
Domain of the equation: x!=0We add all the numbers together, and all the variables
x∈R
2x+10/x-12=0
We multiply all the terms by the denominator
2x*x-12*x+10=0
We add all the numbers together, and all the variables
-12x+2x*x+10=0
Wy multiply elements
2x^2-12x+10=0
a = 2; b = -12; c = +10;
Δ = b2-4ac
Δ = -122-4·2·10
Δ = 64
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{64}=8$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-12)-8}{2*2}=\frac{4}{4} =1 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-12)+8}{2*2}=\frac{20}{4} =5 $
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