4(1+2n)=6(n-3)

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Solution for 4(1+2n)=6(n-3) equation: 



4(1+2n)=6(n-3)

We move all terms to the left:

4(1+2n)-(6(n-3))=0

We add all the numbers together, and all the variables

4(2n+1)-(6(n-3))=0

We multiply parentheses

8n-(6(n-3))+4=0



We calculate terms in parentheses: -(6(n-3)), so:

6(n-3)

We multiply parentheses

6n-18

Back to the equation:

-(6n-18)



We get rid of parentheses

8n-6n+18+4=0

We add all the numbers together, and all the variables

2n+22=0

We move all terms containing n to the left, all other terms to the right

2n=-22

n=-22/2

n=-11

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