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9(x+3)=3(3x+9)
We move all terms to the left:
9(x+3)-(3(3x+9))=0
We multiply parentheses
9x-(3(3x+9))+27=0
We calculate terms in parentheses: -(3(3x+9)), so:We get rid of parentheses
3(3x+9)
We multiply parentheses
9x+27
Back to the equation:
-(9x+27)
9x-9x-27+27=0
We add all the numbers together, and all the variables
=0
x=0/1
x=0
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