32-(x-3)=x/5

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Solution for 32-(x-3)=x/5 equation: 



32-(x-3)=x/5

We move all terms to the left:

32-(x-3)-(x/5)=0

We add all the numbers together, and all the variables

-(x-3)-(+x/5)+32=0

We get rid of parentheses

-x-x/5+3+32=0

We multiply all the terms by the denominator


-x*5-x+3*5+32*5=0

We add all the numbers together, and all the variables

-1x-x*5+175=0

Wy multiply elements

-1x-5x+175=0

We add all the numbers together, and all the variables

-6x+175=0

We move all terms containing x to the left, all other terms to the right

-6x=-175

x=-175/-6

x=29+1/6

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