-5(4y-2)-y=-2(y-2)

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Solution for -5(4y-2)-y=-2(y-2) equation: 



-5(4y-2)-y=-2(y-2)

We move all terms to the left:

-5(4y-2)-y-(-2(y-2))=0

We add all the numbers together, and all the variables

-1y-5(4y-2)-(-2(y-2))=0

We multiply parentheses

-1y-20y-(-2(y-2))+10=0



We calculate terms in parentheses: -(-2(y-2)), so:

-2(y-2)

We multiply parentheses

-2y+4

Back to the equation:

-(-2y+4)



We add all the numbers together, and all the variables

-21y-(-2y+4)+10=0

We get rid of parentheses

-21y+2y-4+10=0

We add all the numbers together, and all the variables

-19y+6=0

We move all terms containing y to the left, all other terms to the right

-19y=-6

y=-6/-19

y=6/19

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