3z+34+2z=7z

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Solution for 3z+34+2z=7z equation: 



3z+34+2z=7z

We move all terms to the left:

3z+34+2z-(7z)=0

We add all the numbers together, and all the variables

-2z+34=0

We move all terms containing z to the left, all other terms to the right

-2z=-34

z=-34/-2

z=+17

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