4z+34+5z-46=6z+42

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Solution for 4z+34+5z-46=6z+42 equation: 



4z+34+5z-46=6z+42

We move all terms to the left:

4z+34+5z-46-(6z+42)=0

We add all the numbers together, and all the variables

9z-(6z+42)-12=0

We get rid of parentheses

9z-6z-42-12=0

We add all the numbers together, and all the variables

3z-54=0

We move all terms containing z to the left, all other terms to the right

3z=54

z=54/3

z=18

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