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2x^2+28x-98=124
We move all terms to the left:
2x^2+28x-98-(124)=0
We add all the numbers together, and all the variables
2x^2+28x-222=0
a = 2; b = 28; c = -222;
Δ = b2-4ac
Δ = 282-4·2·(-222)
Δ = 2560
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{2560}=\sqrt{256*10}=\sqrt{256}*\sqrt{10}=16\sqrt{10}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(28)-16\sqrt{10}}{2*2}=\frac{-28-16\sqrt{10}}{4} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(28)+16\sqrt{10}}{2*2}=\frac{-28+16\sqrt{10}}{4} $
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