3y-8+2(3y+3)=-5(y+2)

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Solution for 3y-8+2(3y+3)=-5(y+2) equation: 



3y-8+2(3y+3)=-5(y+2)

We move all terms to the left:

3y-8+2(3y+3)-(-5(y+2))=0

We multiply parentheses

3y+6y-(-5(y+2))+6-8=0



We calculate terms in parentheses: -(-5(y+2)), so:

-5(y+2)

We multiply parentheses

-5y-10

Back to the equation:

-(-5y-10)



We add all the numbers together, and all the variables

9y-(-5y-10)-2=0

We get rid of parentheses

9y+5y+10-2=0

We add all the numbers together, and all the variables

14y+8=0

We move all terms containing y to the left, all other terms to the right

14y=-8

y=-8/14

y=-4/7

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