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5/6y+1=-1/5y+9
We move all terms to the left:
5/6y+1-(-1/5y+9)=0
Domain of the equation: 6y!=0
y!=0/6
y!=0
y∈R
Domain of the equation: 5y+9)!=0We get rid of parentheses
y∈R
5/6y+1/5y-9+1=0
We calculate fractions
25y/30y^2+6y/30y^2-9+1=0
We add all the numbers together, and all the variables
25y/30y^2+6y/30y^2-8=0
We multiply all the terms by the denominator
25y+6y-8*30y^2=0
We add all the numbers together, and all the variables
31y-8*30y^2=0
Wy multiply elements
-240y^2+31y=0
a = -240; b = 31; c = 0;
Δ = b2-4ac
Δ = 312-4·(-240)·0
Δ = 961
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{961}=31$$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(31)-31}{2*-240}=\frac{-62}{-480} =31/240 $$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(31)+31}{2*-240}=\frac{0}{-480} =0 $
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