3y-4(4y+1)=4-5(-4-y)

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Solution for 3y-4(4y+1)=4-5(-4-y) equation:



3y-4(4y+1)=4-5(-4-y)
We move all terms to the left:
3y-4(4y+1)-(4-5(-4-y))=0
We add all the numbers together, and all the variables
3y-4(4y+1)-(4-5(-1y-4))=0
We multiply parentheses
3y-16y-(4-5(-1y-4))-4=0
We calculate terms in parentheses: -(4-5(-1y-4)), so:
4-5(-1y-4)
determiningTheFunctionDomain -5(-1y-4)+4
We multiply parentheses
5y+20+4
We add all the numbers together, and all the variables
5y+24
Back to the equation:
-(5y+24)
We add all the numbers together, and all the variables
-13y-(5y+24)-4=0
We get rid of parentheses
-13y-5y-24-4=0
We add all the numbers together, and all the variables
-18y-28=0
We move all terms containing y to the left, all other terms to the right
-18y=28
y=28/-18
y=-1+5/9

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