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(2/y+2)-(3/y)=5
We move all terms to the left:
(2/y+2)-(3/y)-(5)=0
Domain of the equation: y+2)!=0
y∈R
Domain of the equation: y)!=0We add all the numbers together, and all the variables
y!=0/1
y!=0
y∈R
(2/y+2)-(+3/y)-5=0
We get rid of parentheses
2/y-3/y+2-5=0
We multiply all the terms by the denominator
2*y-5*y+2-3=0
We add all the numbers together, and all the variables
-3y-1=0
We move all terms containing y to the left, all other terms to the right
-3y=1
y=1/-3
y=-1/3
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