-1/3c+6=9

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Solution for -1/3c+6=9 equation: 



-1/3c+6=9

We move all terms to the left:

-1/3c+6-(9)=0



Domain of the equation: 3c!=0

c!=0/3

c!=0

c∈R



We add all the numbers together, and all the variables

-1/3c-3=0

We multiply all the terms by the denominator


-3*3c-1=0

Wy multiply elements

-9c-1=0

We move all terms containing c to the left, all other terms to the right

-9c=1

c=1/-9

c=-1/9

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