3y-2(2y+3)=5-2(-2-y)

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Solution for 3y-2(2y+3)=5-2(-2-y) equation: 



3y-2(2y+3)=5-2(-2-y)

We move all terms to the left:

3y-2(2y+3)-(5-2(-2-y))=0

We add all the numbers together, and all the variables

3y-2(2y+3)-(5-2(-1y-2))=0

We multiply parentheses

3y-4y-(5-2(-1y-2))-6=0



We calculate terms in parentheses: -(5-2(-1y-2)), so:

5-2(-1y-2)

determiningTheFunctionDomain
-2(-1y-2)+5

We multiply parentheses

2y+4+5

We add all the numbers together, and all the variables

2y+9

Back to the equation:

-(2y+9)



We add all the numbers together, and all the variables

-1y-(2y+9)-6=0

We get rid of parentheses

-1y-2y-9-6=0

We add all the numbers together, and all the variables

-3y-15=0

We move all terms containing y to the left, all other terms to the right

-3y=15

y=15/-3

y=-5

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