1/2b(b-3)=5/2

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Solution for 1/2b(b-3)=5/2 equation: 



1/2b(b-3)=5/2

We move all terms to the left:

1/2b(b-3)-(5/2)=0



Domain of the equation: 2b(b-3)!=0

b∈R



We add all the numbers together, and all the variables

1/2b(b-3)-(+5/2)=0

We get rid of parentheses

1/2b(b-3)-5/2=0

We calculate fractions


=0

b=0/1

b=0

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