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3y-12=6-2(y-1)
We move all terms to the left:
3y-12-(6-2(y-1))=0
We calculate terms in parentheses: -(6-2(y-1)), so:We get rid of parentheses
6-2(y-1)
determiningTheFunctionDomain -2(y-1)+6
We multiply parentheses
-2y+2+6
We add all the numbers together, and all the variables
-2y+8
Back to the equation:
-(-2y+8)
3y+2y-8-12=0
We add all the numbers together, and all the variables
5y-20=0
We move all terms containing y to the left, all other terms to the right
5y=20
y=20/5
y=4
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