0.6(2d-5)=4(7-0.2d)

Solution for 0.6(2d-5)=4(7-0.2d) equation:

0.6(2d-5)=4(7-0.2d)

We move all terms to the left:

0.6(2d-5)-(4(7-0.2d))=0

We add all the numbers together, and all the variables

0.6(2d-5)-(4(-0.2d+7))=0

We multiply parentheses

1.2d-(4(-0.2d+7))-3=0


We calculate terms in parentheses: -(4(-0.2d+7)), so:

4(-0.2d+7)

We multiply parentheses

0d+28

We add all the numbers together, and all the variables

d+28

Back to the equation:

-(d+28)


We get rid of parentheses

1.2d-d-28-3=0

We add all the numbers together, and all the variables

0.2d-31=0

We move all terms containing d to the left, all other terms to the right

0.2d=31

d=31/0.2

d=155