42-(2c+3)=2(c+7)=c

Solution for 42-(2c+3)=2(c+7)=c equation:

42-(2c+3)=2(c+7)=c

We move all terms to the left:

42-(2c+3)-(2(c+7))=0

We get rid of parentheses

-2c-(2(c+7))-3+42=0


We calculate terms in parentheses: -(2(c+7)), so:

2(c+7)

We multiply parentheses

2c+14

Back to the equation:

-(2c+14)


We add all the numbers together, and all the variables

-2c-(2c+14)+39=0

We get rid of parentheses

-2c-2c-14+39=0

We add all the numbers together, and all the variables

-4c+25=0

We move all terms containing c to the left, all other terms to the right

-4c=-25

c=-25/-4

c=6+1/4