3y+5=10(y-3)

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Solution for 3y+5=10(y-3) equation: 



3y+5=10(y-3)

We move all terms to the left:

3y+5-(10(y-3))=0



We calculate terms in parentheses: -(10(y-3)), so:

10(y-3)

We multiply parentheses

10y-30

Back to the equation:

-(10y-30)



We get rid of parentheses

3y-10y+30+5=0

We add all the numbers together, and all the variables

-7y+35=0

We move all terms containing y to the left, all other terms to the right

-7y=-35

y=-35/-7

y=+5

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