Y-4=1/3(x-4)

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Solution for Y-4=1/3(x-4) equation:



-4=1/3(Y-4)
We move all terms to the left:
-4-(1/3(Y-4))=0
Domain of the equation: 3(Y-4))!=0
Y∈R
We multiply all the terms by the denominator
-(1-4*3(Y-4))=0
We calculate terms in parentheses: -(1-4*3(Y-4)), so:
1-4*3(Y-4)
determiningTheFunctionDomain -4*3(Y-4)+1
Wy multiply elements
-12Y(Y+1
Back to the equation:
-(-12Y(Y+1)
We calculate terms in parentheses: -(-12Y(Y+1), so:
-12Y(Y+1
We calculate terms in parentheses: -(-12Y(Y+1), so:
-12Y(Y+1
We calculate terms in parentheses: -(-12Y(Y+1), so:
-12Y(Y+1
We calculate terms in parentheses: -(-12Y(Y+1), so:
-12Y(Y+1
We calculate terms in parentheses: -(-12Y(Y+1), so:
-12Y(Y+1
We calculate terms in parentheses: -(-12Y(Y+1), so:
-12Y(Y+1
We calculate terms in parentheses: -(-12Y(Y+1), so:
-12Y(Y+1
We calculate terms in parentheses: -(-12Y(Y+1), so:
-12Y(Y+1
We calculate terms in parentheses: -(-12Y(Y+1), so:
-12Y(Y+1
We calculate terms in parentheses: -(-12Y(Y+1), so:
-12Y(Y+1
We calculate terms in parentheses: -(-12Y(Y+1), so:
-12Y(Y+1
We calculate terms in parentheses: -(-12Y(Y+1), so:
-12Y(Y+1
We calculate terms in parentheses: -(-12Y(Y+1), so:
-12Y(Y+1
We calculate terms in parentheses: -(-12Y(Y+1), so:
-12Y(Y+1
We calculate terms in parentheses: -(-12Y(Y+1), so:
-12Y(Y+1
We calculate terms in parentheses: -(-12Y(Y+1), so:
-12Y(Y+1
We calculate terms in parentheses: -(-12Y(Y+1), so:
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We calculate terms in parentheses: -(-12Y(Y+1), so:
-12Y(Y+1
We calculate terms in parentheses: -(-12Y(Y+1), so:
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We calculate terms in parentheses: -(-12Y(Y+1), so:
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We calculate terms in parentheses: -(-12Y(Y+1), so:
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We calculate terms in parentheses: -(-12Y(Y+1), so:
-12Y(Y+1
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