3y+2y-y+40=2(-2y+4)

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Solution for 3y+2y-y+40=2(-2y+4) equation: 



3y+2y-y+40=2(-2y+4)

We move all terms to the left:

3y+2y-y+40-(2(-2y+4))=0

We add all the numbers together, and all the variables

4y-(2(-2y+4))+40=0



We calculate terms in parentheses: -(2(-2y+4)), so:

2(-2y+4)

We multiply parentheses

-4y+8

Back to the equation:

-(-4y+8)



We get rid of parentheses

4y+4y-8+40=0

We add all the numbers together, and all the variables

8y+32=0

We move all terms containing y to the left, all other terms to the right

8y=-32

y=-32/8

y=-4

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