7x-3+4=7(x+1)-6

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Solution for 7x-3+4=7(x+1)-6 equation: 



7x-3+4=7(x+1)-6

We move all terms to the left:

7x-3+4-(7(x+1)-6)=0

We add all the numbers together, and all the variables

7x-(7(x+1)-6)+1=0



We calculate terms in parentheses: -(7(x+1)-6), so:

7(x+1)-6

We multiply parentheses

7x+7-6

We add all the numbers together, and all the variables

7x+1

Back to the equation:

-(7x+1)



We get rid of parentheses

7x-7x-1+1=0

We add all the numbers together, and all the variables

=0

x=0/1

x=0

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