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8(x-2)=6(x+2)+2x
We move all terms to the left:
8(x-2)-(6(x+2)+2x)=0
We multiply parentheses
8x-(6(x+2)+2x)-16=0
We calculate terms in parentheses: -(6(x+2)+2x), so:We get rid of parentheses
6(x+2)+2x
We add all the numbers together, and all the variables
2x+6(x+2)
We multiply parentheses
2x+6x+12
We add all the numbers together, and all the variables
8x+12
Back to the equation:
-(8x+12)
8x-8x-12-16=0
We add all the numbers together, and all the variables
-28!=0
There is no solution for this equation
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