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2(3x+5)+3=4(x-2)+2x+21
We move all terms to the left:
2(3x+5)+3-(4(x-2)+2x+21)=0
We multiply parentheses
6x-(4(x-2)+2x+21)+10+3=0
We calculate terms in parentheses: -(4(x-2)+2x+21), so:We add all the numbers together, and all the variables
4(x-2)+2x+21
We add all the numbers together, and all the variables
2x+4(x-2)+21
We multiply parentheses
2x+4x-8+21
We add all the numbers together, and all the variables
6x+13
Back to the equation:
-(6x+13)
6x-(6x+13)+13=0
We get rid of parentheses
6x-6x-13+13=0
We add all the numbers together, and all the variables
=0
x=0/1
x=0
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